Practice question

**Isobaric process** constant pressure, work W = P ΔV = P(V₂ - V₁) = n R ΔT, for expansion ΔV positive W positive, for compression negative, heat Q = n C_p ΔT, ΔU = n C_v ΔT. Isothermal process constant temperature ΔU=0, work W = n R T ln(V₂/V₁) = n R T ln(P₁/P₂), Q = W, heat absorbed equals work done. P₁ V₁^γ = P₂ V₂^γ . P₁ = 1 atm , V₁ = 8 L , V₂ = 2 L , γ = 1.4 . 1 × 8¹.4 = P₂ × 2¹.4 . P₂ = 8¹.42¹.4 = ((8)/(2))¹.4 = 4¹.4 . 4¹.4 =