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Question

How much charge (in coulombs) is required to deposit 0.54 g of nickel from NiSO₄ solution? (Atomic mass of Ni = 54 g/mol, F = 96500 C/mol)

Options

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Explanation

Ni²⁺ + 2e⁻ → Ni . 1 mol Ni (54 g) requires 2F. Moles = (0.54/54) = 0.01 mol , Charge = 0.01 × 2 × 96500 = 1930 C .