Practice question
Question
How many grams of Zn are required to produce 4.48 L of H₂ at STP with excess HCl? (Atomic mass: Zn = 65)
Explanation
Reaction: Zn + 2HCl → ZnCl₂ + H₂. Moles of H₂ = 4.48/22.4 = 0.2 mol. 1 mol H₂ from 1 mol Zn; mass = 0.2 × 65 = 13 g.
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