Practice question
Question
How many coulombs are required to deposit 6.75 g of potassium from a KCl solution? (Atomic mass of K = 39 g/mol, F = 96500 C/mol)
Explanation
K⁺ + e⁻ → K . 1 mol K (39 g) requires 1F. Moles = (6.75/39) = 0.1731 mol , Charge = 0.1731 × 96500 = 16700 C .
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