Practice question
Question
For the reaction CO(g) + Cl₂(g) <=> COCl₂(g) , if Kc = 9 and initial concentrations are [CO] = 0.3 M , [Cl₂] = 0.3 M , what is [COCl₂] at equilibrium?
Explanation
Let [COCl₂] = x , [CO] = 0.3 - x , [Cl₂] = 0.3 - x . Kc = ([COCl₂]/[CO][Cl₂]) = (x/(0.3 - x)²) = 9 . Solving, sqrt(x/0.3 - x) = 3 , (x/0.3 - x) = 9 , x = 2.7 - 9x , 10x = 2.7 , x = 0.27 M .
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