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Practice question

MCQ

Question

For 2A(g) + B(g) <=> 2C(g) , Kp = 4 at 500 K. If initial pressures are PA = 2 atm , PB = 1 atm , what is PC at equilibrium?

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Explanation

Let PC = 2x , PA = 2 - 2x , PB = 1 - x . Kp = ((PC)²/PA² PB) = ((2x)²/(2 - 2x)² (1 - x)) = 4 , (4x²/(4 - 4x + 4x²)(1 - x)) = 4 , x ≈ 0.8 , PC = 1.6 atm .

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