Practice question
Question
Calculate Δ H for C(s) + H₂(g) + O₂(g) → CH₃OH(l) given: CH₃OH(l) + (3/2)O₂(g) → CO₂(g) + 2H₂O(l), Δ H = -726.5 kJ/mol; C(s) + O₂(g) → CO₂(g), Δ H = -393.5 kJ/mol; H₂(g) + (1/2)O₂(g) → H₂O(l), Δ H = -285.8 kJ/mol.
Explanation
Reverse first: Δ H = 726.5 kJ. Second: Δ H = -393.5 kJ. Third (×2): Δ H = -571.6 kJ. Add: 726.5 - 393.5 - 571.6 = -238.6 kJ/mol.
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