Practice question

For a rod pivoted at its center: I = 112ML2. M = 4kg, L = 2.5m. I = 112×4×(2.5)2 = 4×6.2512 = 2512≈2.08kg m2. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.08 kg m². This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.