Practice question
Question
A 1kg particle moves with velocity v\=3i^+4j^m/s at position r\=2j^m. What is the z-component of its angular momentum about the origin?
Explanation
Angular momentum: L = r×p, where p = mv = 1×(3i^+4j^). L = |i^j^k^020340| = k^(0×4−2×3) = −6k^kgm2/s. Z-component = −6kg m2/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to -6 kg m²/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.