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Practice question

MCQ

Question

A stone is thrown upwards at 35m/s from a 45m cliff. How far below the cliff’s edge is it after 8s? (Take g\=10m/s2)

Options

Choose one · Correct answer highlighted

Explanation

Displacement: y=35⋅8−12⋅10⋅(8)2=280−320=−40m. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 85 m as the result, so option A is correct.

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