Practice question
Question
A solution of two volatile liquids has vapor pressures of 200 mm Hg and 300 mm Hg for pure components. If the total vapor pressure is 240 mm Hg, what is the mole fraction of the second component in the vapor phase?
Explanation
Liquid phase: 240 = 200 x₁ + 300 (1 - x₁) . 240 = 200 x₁ + 300 - 300 x₁ , 100 x₁ = 60 , x₁ = 0.6 , x₂ = 0.4 . Vapor phase: y₂ = (300 × 0.4/240) = 0.5 .
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