Practice question

Given: A solution contains 15 g of glycerol ( C₃H₈O₃ ) in 285 g of water. What is the molality of the solution? (Molar mass: C₃H₈O₃ = 92 g/mol ) These values define the system as per NCERT data. Formula: Moles of glycerol = 15/92 = 0.163 mol. This is standard NCERT relation. Substitution & Calculation: Mass of solvent in kg = 285/1000 = 0.285 kg . Molality = 0.163/0.285 = 0.572 mol/kg . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.