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Question

A second-order reaction has a rate constant of 0.05 L mol⁻¹ s⁻¹ and an initial concentration of 0.4 mol L⁻¹. What is the time for 50% completion?

Options

Choose one · Correct answer highlighted

Explanation

t½ = 1/(k[A]₀) = 1/(0.05×0.4) = 50 s.