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#half-life

53 public questions tagged with this topic.

CHEMISTRY

A first-order reaction has a rate constant of 0.0462 min^{-1 . What is the half-life in minutes?

Given: A first-order reaction has a rate constant of 0.0462 min^{-1 . What is the half-life in minutes? These values define the system as per NCERT data. Formula: t_{1/2 = 0.693/k = 0.693/0.0462 = 15 min .. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10⁻⁵, 236 J kg⁻¹ K⁻¹, CH₃CH₂NH₂ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Relevant Chemistry topic covering principles and examples as per NCERT.

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CHEMISTRY

A first-order reaction has a rate constant of 0.01732 min^{-1 . What is the half-life in minutes?

Given: A first-order reaction has a rate constant of 0.01732 min^{-1 . What is the half-life in minutes? These values define the system as per NCERT data. Formula: t_{1/2 = 0.693/k = 0.693/0.01732 = 40 min .. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10⁻⁵, 236 J kg⁻¹ K⁻¹, CH₃CH₂NH₂ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Relevant Chemistry topic covering principles and examples as per NCERT.

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CHEMISTRY

The rate constant for a zero-order reaction is 1.5 × 10⁻²mol L^{-1 min^{-1 . What is the half-life if the initial concen

Given: The rate constant for a zero-order reaction is 1.5 × 10⁻²mol L^{-1 min^{-1 . What is the half-life if the initial concentration is 0.3 M? These values define the system as per NCERT data. Formula: For zero order, t_{1/2 = frac[R]_02k = frac0.32 × 1.5 × 10⁻²= 10 min .. This is standard NCERT relation. Substitution & Calculation: Substituting values and simplifying step by step as per NCERT method. Result: The computed value matches expected outcome and confirms correct choice as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom, Periodicity and relevant Chemistry topic, Topic: Mole concept and periodic trends.

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