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Question

A neutron (1u) at 4×106m/s collides elastically with a carbon (12u). What fraction of its kinetic energy is retained?

Options

Choose one · Correct answer highlighted

Explanation

Kinetic energy K=½mv² and potential U=mgh per NCERT. Energy conservation K+U=constant for conservative forces. Substituting m, v, h gives 121169 as energy, matching option A.

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