Practice question
Question
A glass slab of volume 0.01m3 is subjected to a hydraulic pressure of 2×106N/m2. If the bulk modulus of glass is 3.7×1010N/m2, what is the change in volume?
Explanation
Bulk modulus: B = −pΔVV. Rearrange: ΔVV = −pB = −2×1063.7×1010≈−5.41×10−5. Change in volume: ΔV = ΔVV×V = −5.41×10−5×0.01≈−5.41×10−7m3. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 5.41×10−7m3. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.