Practice question
Question
A gas at 1atm and 27∘C occupies 5L. What will be its volume at 2atm and 127∘C?
Explanation
Given: P1 = 1atm, V1 = 5L, T1 = 27∘C = 300K, P2 = 2atm, T2 = 127∘C = 400K. Ideal gas law: P1V1T1 = P2V2T2. V2 = V1×P1P2×T2T1 = 5×12×400300 = 5×0.5×1.33≈3.33L.
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