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Practice question

MCQ

Question

A gas occupies 5L at 2atm and 27∘C. If the pressure is increased to 4atm and volume reduced to 3L, what is the final temperature in Celsius?

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Explanation

Given: V1 = 5L, P1 = 2atm, T1 = 27∘C = 300K, P2 = 4atm, V2 = 3L. P1V1T1 = P2V2T2. T2 = T1×P2P1×V2V1 = 300×42×35 = 300×2×0.6 = 360K. tC = T2−273.15 = 360−273.15≈86.85∘C≈87∘C.

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