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Practice question

MCQ

Question

A cell Cu(s) | Cu²⁺(0.01 M) || Cl₂(g)(0.5 atm) | Cl⁻(0.05 M) | Pt(s) operates at 298 K. What is the cell potential? (Given: E°Cu²⁺/Cu = 0.34 V , E°Cl_₂/Cl⁻ = 1.36 V )

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Explanation

E°cell = 1.36 - 0.34 = 1.02 V . Ecell = 1.02 - (0.059/2) log ([Cu²⁺][Cl⁻]²/PCl_₂) = 1.02 - 0.0295 log (0.01 × 0.0025/0.5) = 1.02 + 0.053 = 1.073 V .

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