Practice question
Question
A bacteria l culture, with the molecular formula - C ₄.₄ H ₇.₃ 0 ₁.₂ N ₀.₈₆ is cultivated under aerobic conditions with hexadecane (C16H34) as substrate. The growth can be described by equation: C ₁₆ H ₃₄ + 16.28O ₂ + 1.42NH ₃ ➔ 1.65C ₄.₄ H ₇.₃ O ₁.₂ N ₀.₈₆ + 8.74CO ₂ + 13.11 H ₂ O. Assuming 100% conversion, the yield of cell mass from hexadecane will be
Explanation
This outcome reflects microbial physiology, where growth regulation and host interactions follow molecular programs. Option B captures this correctly because it corresponds to prokaryotic and viral strategies, consistent with textbook descriptions and experimental observations in microbiology.
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