Practice question

Given: A 0.3 kg stone is whirled in a horizontal circle of radius 1.6 m at 45 rev/min . What is the tension? (Take g = 10 m/s² ) These values define the system as per NCERT data. Formula: Angular speed: omega = 45 × 2π/60 = 3π/2 rad/s. This is standard NCERT relation. Substitution & Calculation: omega² = (3π/2)² = 9π²/4 approx 22.21 . Tension: T = m omega² r = 0.3 × 22.21 × 1.6 . T approx 0.3 × 22.21 × 1.6 approx 10.66 N . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.