Practice question
Question
A 40 V battery with negligible internal resistance is connected to a cubical network of 12 resistors, each 4 Ω . What is the total current?
Explanation
Given:
A 40 V battery with negligible internal resistance is connected to a cubical network of 12 resistors, each 4 Ω . What is the total current?
These values define the system as per NCERT data.
Formula:
Equivalent resistance: R_{eq = 5/6 R = 5/6 × 4 = 20/6 approx 3.33 Ω.
This is standard NCERT relation.
Substitution & Calculation:
Total current: I = fracVR_{eq = frac4020/6 = 40 × 6/20 = 12 A .
Result:
The computed value matches expected outcome and confirms correct choice as per NCERT.
Discussion
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