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Question

What is the freezing point depression of a solution containing 15 g of mannitol (molar mass = 182 g/mol) in 500 g of water? ( Kf = 1.86 K kg mol⁻¹ )

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Explanation

Moles of mannitol = (15/182) ≈ 0.0824 mol . Molality = (0.0824/0.5) ≈ 0.1648 mol/kg . Δ Tf = 1.86 × 0.1648 ≈ 0.3065 K .

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