Practice question
Question
Vectors a\=−4i^+3j^ and b\=2i^+5j^ are given. What is the magnitude of a×b?
Explanation
a×b = |i^j^k^−430250| = k^((−4)×5−3×2) = k^(−20−6) = −26k^. Magnitude = 26. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 26. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
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