Practice question
Question
Two waves of frequencies 510 Hz and 514 Hz interfere. How many beats are heard in 15 seconds?
Explanation
**Frequency shift** proportional to source speed relative to wave speed v. Understanding sign convention for approaching versus receding is key, with approaching increasing frequency and receding decreasing, central to Doppler applications. Beat frequency: vbₑₐt = 514 - 510 = 4 Hz . Beats in 15 s: 4 × 15 = 60 . Using v = fλ and standing-wave condition fₙ = n v/(2L) or v/(4L) as applicable, calculation yields 60, illustrating frequency-length-speed interdependence and quantization by boundaries. This aligns with NCERT Class 11 treatment, emphasizing conservation, symmetry and dimensional consistency useful for CBSE, NEET and CUET.
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