Practice question

X = (4×0)+(6×8)4+6 = 4810 = 4.8. Y = (4×7)+(6×3)4+6 = 28+1810 = 4.6. Distance = (4.8)2+(4.6)2 = 23.04+21.16 = 44.2≈6.65m. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 6.65 m. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.