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Question

The molar conductivity of a 0.1 M KCl solution is 129 S cm² mol⁻¹. If the conductivity of the solution is 0.0129 S cm⁻¹, what is the concentration used in the calculation?

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Explanation

Lambdam = (kappa × 1000/c) . 129 = (0.0129 × 1000/c) , so c = (12.9/129) = 0.1 M .

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