Practice question
Question
The limiting molar conductivity of SrCl₂ is 260 S cm² mol⁻¹. If λ°Sr²⁺ = 118 S cm² mol⁻¹ , what is λ°Cl⁻ ?
Explanation
Lambdam° = λ°Sr²⁺ + 2λ°Cl⁻ . 260 = 118 + 2λ°Cl⁻ , 2λ°Cl⁻ = 142 , λ°Cl⁻ = 71 S cm² mol⁻¹ .
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