Practice question
Question
In electrolysis, 0.635 g of Cu (atomic mass 63.5 g/mol) is deposited from CuSO₄ using 0.5 A for 3860 s. What is the percentage efficiency of the process? (F = 96500 C/mol)
Explanation
Charge = 0.5 × 3860 = 1930 C . Theoretical mass = (1930/96500) × (63.5/2) = 0.02 × 31.75 = 0.635 g . Efficiency = (Actual/Theoretical) × 100 = (0.635/0.635) × 100 = 100% .
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