Practice question
Question
How much heat is needed to convert 0.1kg of mercury at −39∘C to liquid at 357∘C? (Specific heat of solid mercury = 140J kg−1K−1, latent heat of fusion = 0.12×105J kg−1, specific heat of liquid mercury = 140J kg−1K−1)
Explanation
Q1 = 0.1×140×(39) = 546J (solid from -39°C to 0°C). Q2 = 0.1×0.12×105 = 1200J (melting). Q3 = 0.1×140×357 = 4998J (liquid from 0°C to 357°C). Total: Q = 546+1200+4998 = 6744J = 6.744kJ.
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