Practice question
Question
For an ideal gas ( γ = 1.67 ) compressed adiabatically from V₁ = 12 L to V₂ = 3 L, starting at T₁ = 300 K, calculate thework done on the gasif Cv = 12.47 J mol⁻¹K⁻¹ . (Assume n=1 mol.)
Explanation
For an adiabatic ideal-gas process, T₂ = T₁ (V₁/V₂)γ⁻¹ = 300 × 4⁰.⁶⁷ ≈ 300 × 2.5315 = 759.45 K .
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