Practice question
Question
For 2X(g) <=> Y(g) + Z(g) , Kc = 0.01 at 400 K. If 1 mol X is in a 1 L vessel, what is the degree of dissociation at equilibrium?
Explanation
Initial: [X] = 1 M . Let α be the degree of dissociation, [X] = 1 - α , [Y] = [Z] = (α/2) . Kc = ([Y][Z]/[X]²) = (((α/2))²/(1 - α)²) = 0.01 , (α²/4(1 - α)²) = 0.01 , (α/1 - α) = 0.2 , α = 0.2 - 0.2α , 1.2α = 0.2 , α = 0.167 .
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