Practice question
Question
An electron has a de Broglie wavelength of 2.0 × 10⁻¹⁰ m. What is its kinetic energy in joules? (h = 6.626 × 10⁻³⁴ J s, mₑ = 9.1 × 10⁻³¹ kg)
Explanation
KE = h²/(2mλ²) = (6.626×10⁻³⁴)² / (2 × 9.1×10⁻³¹ × (2.0×10⁻¹⁰)²) = 6.02×10⁻¹⁹ J.
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