Practice question

Given: A spring system has m = 1.2 kg, k = 480 N/m, A = 6 cm . What is the potential energy at x = 3 cm ? These values define the system as per NCERT data. Formula: Potential energy: U = 1/2 k x². This is standard NCERT relation. Substitution & Calculation: k = 480 N/m, x = 0.03 m . U = 0.5 × 480 × (0.03)² = 0.5 × 480 × 0.0009 = 0.216 J . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.