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Question

A satellite near Earth has a period of 87 minutes. What is its period at h\=6RE? (RE\=6.4×106m)

Options

Choose one · Correct answer highlighted

Explanation

T2∝(RE+h)3. T02 = kRE3, h = 6RE, r = 7RE. T2 = k(7RE)3 = 343kRE3. T = T0343 = 87×18.52≈1611min. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1620 min. This satisfies dimensional consistency and physical conditions given, so option D is scientifically correct.