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Question

A railway carriage having a mass of 5000 kg is moving with a speed of 12 m/sec on a curve of 150 m radius. If the track is level (i.e. without super elevation) find the lateral thrust on the outer rail?

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Explanation

Lateral thrust equals centripetal force required for circular motion m v²/r. With m=5000 kg, v=12 m/s, r=150 m, force=5000×144/150=4800 N. Without superelevation, outer rail must provide this inward force, creating outward thrust.

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