Practice question
Question
A pendulum bob of 1kg completes a vertical circle of radius 2m with minimum speed at the bottom. What is the speed at the top? (Take g\=10m/s2)
Explanation
At top, minimum speed vC=gL=10×2=20≈4.47m/s. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 4 m/s as the result, so option A is correct.
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