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Question

A mass oscillates with \( v = -12 \cos (4t) \) (in m/s). What is its amplitude?

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Explanation

**Periodic motion** repeats after fixed period T, x(t+T)=x(t), while oscillatory motion involves to-and-fro about equilibrium. SHM is special periodic motion where restoring force proportional to displacement, F = -k x, acceleration a = -ω² x, leading to sinusoidal displacement x = A cos(ωt + φ). Velocity: v = -ω A sin (ω t) , but given v = -12 cos (4t) . ω = 4 s⁻¹, vₘₐₓ = ω A = 12 ⇒ A = (12/4) = 3 m . Applying x = A cos(ωt + φ), v = -ωA sin(ωt + φ), a = -ω²x and E = ½kA² = ½mω²A², result 3.0 m

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