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Practice question

MCQ

Question

A fluid flows through a pipe with speeds v1\=2m/s at height h1\=1m and v2\=4m/s at h2\=0m. If P1\=1.2×105Pa, find P2. (ρ\=1000kg/m3, g\=10m/s2)

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Explanation

Bernoulli’s equation: P1+12ρv12+ρgh1 = P2+12ρv22+ρgh2. P1 = 1.2×105, v1 = 2m/s, h1 = 1m, v2 = 4m/s, h2 = 0m. Left: 1.2×105+12×1000×4+1000×10×1 = 1.2×105+2000+10000 = 1.32×105. Right: P2+12×1000×16 = P2+8000. 1.32×105 = P2+8000, P2 = 1.24×105Pa.

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