Skip to content

Question

A dipole with \( p = 6 \times 10^{-9} \, \text{C m} \) is at 60° to a field \( E = 3 \times 10^4 \,
\text{N/C} \). What is the torque?

Options

Choose one · Correct answer highlighted

Explanation

**Dipole moment** governs torque and energy in external field. Axial field stronger than equatorial, torque maximum at θ = 90°, zero when aligned. Work done rotating dipole relates to ΔU = pE(1 - cosθ), explaining stable equilibrium at θ = 0°. tau = p E sin θ . tau = 6 × 10⁻⁹ × 3 × 10⁴ × sin 60° = 18 × 10⁻⁵ × (√(3)/2) = 1.56 × 10⁻⁴ N m . Substituting values gives 1.56 × 10⁻⁴ N m, which matches expected magnitude for this electrostatic configuration, confirming Coulomb's and Gauss's principles and charge quantization consistency.

Discussion

Comments

0 comments

No comments yet. Be the first to start the discussion.