Practice question

MCQ

Question

A brass wire of length 1.6m and cross-sectional area 2×10−6m2 is stretched by a force producing a stress of 4×107N/m2. If the Young's modulus of brass is 9×1010N/m2, what is the strain?

Options

Choose one · Correct answer highlighted

4×10−4 5×10−4 3×10−4 4.44×10−4 Correct

Explanation

Young's modulus: Y = StressStrain. Strain: Strain = StressY = 4×1079×1010≈4.44×10−4. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 4.44×10−4. This satisfies dimensional consistency and physical conditions given, so option D is scientifically correct.

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