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Practice question

MCQ

Question

A body is launched from Earth at 14km/s. What is its speed at infinity? (Escape speed = 11.2km/s)

Options

Choose one · Correct answer highlighted

Explanation

vf2 = vi2−ve2. vf2 = (14)2−(11.2)2 = 196−125.44 = 70.56. vf = 70.56≈8.4km/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 8.4 km/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

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