Skip to content

Question

A 1kg particle moves with velocity v\=−3i^+4j^m/s at r\=2i^m. What is the z-component of its angular momentum?

Options

Choose one · Correct answer highlighted

Explanation

L = r×p = |i^j^k^200−340| = k^(2×4−0×(−3)) = 8k^kg m2/s. Z-component = 8kg m2/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 8 kg m²/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Discussion

Comments

0 comments

No comments yet. Be the first to start the discussion.