Practice question

Given: 2 moles of an ideal gas expand isothermally from 6 L to 18 L against a constant pressure of 1 atm at 340 K. Calculate the work done (1 L · atm = 101.3 J). Formula: w = -p_{ex Δ V. Substitution & Calculation: Δ V = 18 - 6 = 12 L, p_{ex = 1 atm. w = -1 × 12 = -12 L · atm = -12 × 101.3 = -1215.6 J = -1.22 kJ. Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.