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Question

What is the emf of a cell with the reaction Mg(s) + 2Ag⁺(aq) → Mg²⁺(aq) + 2Ag(s) at standard conditions, given E°Mg²⁺/Mg = -2.36 V and E°Ag⁺/Ag = 0.80 V ?

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Explanation

E°cell = E°cathode - E°anode = 0.80 - (-2.36) = 3.16 V .

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