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L = nh/2π, for n=5, L = 5 × 6.626×10⁻³⁴ / (2×3.14) = 5.275×10⁻³⁴ J s.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Shapes of Orbitals - s p d f and Nodes and Radial Probability
λ = h/(mv) = 6.65×10⁻¹⁰ m.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Quantum Mechanical Model - de Broglie Heisenberg and Schrodinger
n=6. For Li²⁺ (Z=3), r₆ = 36/3 × 5.29×10⁻¹¹ = 6.348×10⁻¹⁰ m.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Electronic Configuration - Aufbau Pauli Hund and Stability
L = 5h/2π = 5.275×10⁻³⁴ J s.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Atomic Models - Thomson Rutherford and Bohr Model
v₃ = 2.19×10⁶ m s⁻¹. KE = ½mv² = 2.18×10⁻¹⁸ J.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Atomic Models - Thomson Rutherford and Bohr Model
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