Practice question
Question
The velocity of an electron in the second orbit of a hydrogen atom is 1.095 × 10⁶ m s⁻¹. What is its de Broglie wavelength in this orbit? (h = 6.626 × 10⁻³⁴ J s, mₑ = 9.1 × 10⁻³¹ kg)
Explanation
λ = h/(mv) = 6.65×10⁻¹⁰ m.
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