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Question

The angular momentum of an electron in the sixth orbit of Li²⁺ is 6.33 × 10⁻³⁴ J s. What is its radius? (h = 6.626 × 10⁻³⁴ J s, r₁ for H = 5.29 × 10⁻¹¹ m)

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Explanation

n=6. For Li²⁺ (Z=3), r₆ = 36/3 × 5.29×10⁻¹¹ = 6.348×10⁻¹⁰ m.

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