Practice question

Given: What is the potential of a hydrogen electrode in a solution with pH = 5 at 298 K, given E⁰ = 0 V ? Formula: For H+ + e- -> 1/2 H₂, E = E⁰ - 0.059/1 log frac1[H^+]. Substitution & Calculation: [H^+] = 10⁻⁵, E = 0 - 0.059 × 5 = -0.295 V . Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.