Practice question
Question
For the reaction N₂O(g) + 1/2O₂(g) -> 2NO(g), if Δ H = 99.25 kJ/mol at 298 K, what is Δ U (R = 8.314 J/mol · K)?
Explanation
Given:
For the reaction N₂O(g) + 1/2O₂(g) -> 2NO(g), if Δ H = 99.25 kJ/mol at 298 K, what is Δ U (R = 8.314 J/mol · K)?
Formula:
Δ n_g = 2 - (1 + 0.5) = 0.5, RT = 2.48 kJ.
Substitution & Calculation:
Δ H = Δ U + Δ n_g RT. Δ U = 99.25 - 0.5 × 2.48 = 98.01 kJ/mol.
Final Result:
The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.
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